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6d^2-11d-4=0
a = 6; b = -11; c = -4;
Δ = b2-4ac
Δ = -112-4·6·(-4)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{217}}{2*6}=\frac{11-\sqrt{217}}{12} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{217}}{2*6}=\frac{11+\sqrt{217}}{12} $
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